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matematicka hádanka


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3 chlapi se jdou ubytovat pokoj stoji 30 Kč. každy da 10 Kč. recepčnimu dojde že pokoj stoji 25 kč a pošle poslička s 5 korunou za chlapama na pokoj. Nevi jak to rozdělit tak da každemu po koruně a 2 koruny si necha....takžde 3 chlapi krat 9 Kč(protože každy dostal korunu zpět) = 27Kč + posliček si nechal 2 Kč = 29,- kde je ta jedna koruna?

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Problem je v "nedelitelnosti" celych cisel. Pokud bychom chteli pocitat stale se soucasnym delenim 3 - museli bychom postupovat takto:

1. chlapi platili kazdy 10kc - coz je spolu 30kc

2. spravne meli platit 25kc - coz znamena, ze kazdy mel dat 8,333...kc

3. pokud pikolik vratil kazdemu 1kc, pak podil kazdeho na celkove uhrade neni 9kc, ale 9,333...kc (coz je vynasobeno tremi 28kc)

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